sabato 9 ottobre 2010

Problem 6

The sum of the squares of the first ten natural numbers is,
12 + 22 + ... + 102 = 385

The square of the sum of the first ten natural numbers is,
(1 + 2 + ... + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

solution = sumSquare - squareSum
    
squareSum = sum $ map (^2) [1..100]
sumSquare = (^2) $ sum [1..100]

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